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-1000=-4.9(x)^2
We move all terms to the left:
-1000-(-4.9(x)^2)=0
We get rid of parentheses
4.9x^2-1000=0
a = 4.9; b = 0; c = -1000;
Δ = b2-4ac
Δ = 02-4·4.9·(-1000)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*4.9}=\frac{-140}{9.8} =-14+2.8/9.8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*4.9}=\frac{140}{9.8} =14+2.8/9.8 $
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